b^2x^2-3bx-4=0

Solution for b^2x^2-3bx-4=0 equation:

Simplifying
b2x2 + -3bx + -4 = 0

Reorder the terms:
-4 + -3bx + b2x2 = 0

Solving
-4 + -3bx + b2x2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-1 + -1bx)(4 + -1bx) = 0

Subproblem 1
Set the factor '(-1 + -1bx)' equal to zero and attempt to solve:

Simplifying
-1 + -1bx = 0

Solving
-1 + -1bx = 0

Move all terms containing b to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -1bx = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1bx = 0 + 1
-1bx = 0 + 1

Combine like terms: 0 + 1 = 1
-1bx = 1

Divide each side by '-1x'.
b = -1x-1

Simplifying
b = -1x-1
Subproblem 2
Set the factor '(4 + -1bx)' equal to zero and attempt to solve:

Simplifying
4 + -1bx = 0

Solving
4 + -1bx = 0

Move all terms containing b to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1bx = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1bx = 0 + -4
-1bx = 0 + -4

Combine like terms: 0 + -4 = -4
-1bx = -4

Divide each side by '-1x'.
b = 4x-1

Simplifying
b = 4x-1
Solution
b = {-1x-1, 4x-1}